The volume of empty space in the Can is \(8.49 \ in^{3}\).
Cylinder:
A cylinder is a three-dimensional solid that holds two parallel bases joined by a curved surface, at a fixed distance. These bases are normally circular in shape or circle, and the center of the two bases are joined by a line segment, which is called the axis.
The given data are:
Diameter of the ball (\(d\))\(=2.25 \ in\)
The radius of the ball (\(r\))\(=1.125 \ in\)
Diameter of Can (\(D\))\(=2.25 \ in\)
The radius of Can (\(R\))\(=2.25/2=1.125 \ in\)
Height of can (\(H\))\(=6.75 \ in\)
\(\therefore\)The volume of one ball\(=V_{1} =\frac{4}{3}\pi r^{3}\)
\(V_{1}=\frac{4}{3}\ast 3.14\ast 1.125^{3} \\ V_{1}=5.96109 \ in^{3}\)
The volume of 3 balls,
\(V_{2}=3\ast V_{1}=3\ast 5.96109=17.88327 \ in^{3}\)
The volume of Can (\(V_3\))\(=\pi \ast R^{2} \ast H\)
\(V_3=\pi \ast1.125^2 \ast6.75\\V_3=26.8249\)
The volume of empty space in Can(\(V\))\(=V_3-V_2\)
\(V=26.8249-17.88327\\V=8.94163\approx 8.94\)
Learn more about the topic Cylinder: https://brainly.com/question/26401820
