HELP

What is the standard form equation of the line shown below?


Graph of a line going through negative 2, 3 and 1, negative 3


y + 3 = −2(x − 1)

y = −2x − 1

2x + y = −1

−2x − y = 1

HELP What is the standard form equation of the line shown below? Graph of a line going through negative 2, 3 and 1, negative 3 y + 3 = 2(x 1) y = 2x 1 2x + y = class=

Verified Answer :

Standard form means:
Ax+By=C
Where A is the coefficient of x, B is the coefficient of y, and C is the y intercept.

It's true that some of those say the same thing but your answer must be in that form because that is what the question asks. So it should be 2x+y=-1

Answer:

\(2x+y=-1\)

Step-by-step explanation:

The given points are

\((-2,3)\)

\((1,-3)\)

To find the expression of the line shown, first we need to find the slope between the two given points, which the following formula

\(m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} } =\frac{-3-3}{1-(-2)}=\frac{-6}{3}=-2\)

Now, we have the slope, then we use the point-slope formula, and replace the slope and one point of the given

\(y-y_{1}=m(x-x_{1})\\y-3=-2(x-(-2))\\y=-2x-4+3\\y=-2x-1\)

But, the standard form is like \(Ax+Bx=C\)

So,

\(2x+y=-1\)

Therefore, the right choice is the third option.