Verified Answer :

mariamikayla

\(\angle \ a+ \angle \ b+ \angle \ c =180^0 \\\\ \angle a=\angle \ c=65^0 \\\\ 65^0+65^0+\angle \ b=180^0 \\\\ 130^0+\angle \ b=180^0 \\\\ \angle \ b=180^0-130^0 \\\\ \boxed{\angle \ b=50^0}\)

eu99li

The sum of the angles of a triangle is 180°.
x+ 65°+65°=180° /-130°
x=50°
⇒ the 3rd angle is \(50°\)

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