Write a linear factorization of the function.


f(x) = x4+ 9x2


f(x) = x2(x + 3i)(x - 3i)


f(x) = x2(x + 3i)2


f(x) = x2(3x + i)(3x - i)


f(x) = x2(3x + i)

Verified Answer :

f(x) = x^4 + 9x^2 = x^2(x^2 + 9) = x^2(x^2 - (-9)) = x^2(x - sqrt(-9))(x + sqrt(-9)) = x^2(x + 3i)(x - 3i)

Answer:

\(f(x)=x^2(x+3i)(x-3i)\)

Step-by-step explanation:

Given expression is,

\(f(x)=x^4+9x^2\)

\(=x^2\{x^2+9\}\)   ( Converse of distributive property )

\(=x^2\{x^2-i^2.9\}\)    ( i² = -1 )

\(=x^2\{(x)^2-i^2(3)^2\}\)

\(=x^2\{(x)^2-(3i)^2\}\)

\(=x^2(x+3i)(x-3i)\)      ( a² - b² = (a+b)(a-b) )

Since, further factorization is not possible,

Thus, the required linear factorization of the function is,

\(f(x)=x^2(x+3i)(x-3i)\)

First option is correct.