h5enpan9tainmarielan
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can someone show me the work for this?


Suppose y = sqrt (2x + 1) where x and y are functions of t.?


suppose y = sqrt (2x + 1) ,where x and y are functions of t.

AIf dx/dt = 3, find dy/dt when x = 4.

dy / dt = ?

BIf dy/dt = 5, find dx/dt when x = 12.

dx/dt= ?

Verified Answer :

meerkat18

we are given the equation or function  y = sqrt (2x + 1). The derivative of the equation is expressed as 

1. dy/dt = 0.5 2 (2x + 1)^-0.5 dx/dt
when x = 4 and dx/dt =3
dy/dt = 0.5 2 3(24 + 1)^-0.5 
dy/dt = 1

2. dy/dt = 0.5 2 (2x + 1)^-0.5 dx/dt
 If dy/dt = 5, find dx/dt when x = 12.
    5= 0.5 2 (212 + 1)^-0.5 dx/dt
   dx/dt = 1 

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