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A 1.0 kg wood block is launched up a wooden ramp that is inclined at a 40° angle. The block's initial speed is 11 m/s. (Use µk = 0.20 for the coefficient of kinetic friction for wood on wood.)

AWhat vertical height does the block reach above its starting point?
BWhat speed does it have when it slides back down to its starting point?

Verified Answer :

meerkat18

The kinetics formula that applies to this problem is 
1. To find height, we use 1/2mv12−mg∗μ∗h sin θ = mgh where μ is equal to 0.20, v is 11 m/s and θ is 40 degrees. we cancel mass, h is equal to 5.47 meters.
2. The final speed is from 2(ug) h sin θ  = vf2 
2(0.29.8)  sin 40 5.47= vf2 ; vf is equal to 3.71 m/s.




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