Verified Answer :

calculista

In order to find the roots of the cubic equations by graphing you have to follow those steps

we have

\(x^3+2x^2-16x-32\)

we know that

The roots of the function are the values of x when the value of the function is equal to zero

Using a graphing tool

see the attached figure

The roots are

\(x=-4\ x=-2\ x=4\)

therefore

the answer is

\(x=-4\ x=-2\ x=4\)


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isyllus

Answer:

The roots are -2,-4 and 4

B, C and E are correct.

Step-by-step explanation:

Given: \(x^3+2x^2-16x-32\)

We are given a cubic polynomial. We have to find the roots of the polynomial. Roots are the x-intercept of polynomial.

First we will set the polynomial to 0 and solve for x

\(x^3+2x^2-16x-32=0\)

\(x^2(x+2)-16(x+2)=0\)

\((x+2)(x^2-16)=0\)

\((x+2)(x+4)(x-4)=0\)                               \(\because a^2-b^2=(a+b)(a-b)\)

Now, we will set each factor to zero and solve for x

\(x+2=0\ \ \ \ x+4=0\ \ \ \ \ \ \ x-4=0\)

\(x=-2,-4,4\)

Hence, The roots are -2,-4 and 4

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