An object is traveling around a circle with a radius of 20 meters. If in 10 seconds a central angle of 1/5 radian is swept out, what is the linear speed of the object?
The linear speed of the object is the ratio between the measure of the arc it had traveled and the time. For the length of the arc,
2π x (20 m) x (0.2 rad/ 2π rad) = 4 meters
Divide this by the time, 10 s. Thus, the linear speed is equal to 0.4 m/s.
Answer:
The linear speed is 0.4 m/s
Step-by-step explanation:
Given,
The radius of the circle = 20 meters,
The central angle made by the object that travelling around the circle = \(\frac{1}{5}\) radian,
So, the distance covered by the object = The radius of the circle × Central angle made by the object ( in radians )
\(=20\times \frac{1}{5}\)
\(=4\text{ meters}\)
Now, the time taken by the object in travelling = 10 seconds,
\(\text{Speed}=\frac{\text{Distance}}{\text{Time}}\)
Hence, the linear speed of the object = \(\frac{4}{10}\)
= 0.4 m/s