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The balanced chemical reaction is:

Ca + Cl2 =  CaCl2

We are given the amount of calcium metal to be used for this reaction. This will be the starting point for the calculations.

56 g Ca ( 1 mol Ca / 40.08 g Ca) (1 mol Cl2 / 1 mol Ca) ( 22.414 L Cl2 / 1 mol Cl2 ) = 31.32 L Cl2 gas produced from the reaction

Answer:

31.36 L of chlorine gas will react with 56 g of calcium.

Explanation:

\(Ca + Cl_2\rightarrow CaCl_2\)

Mass of calcium = 56 g

Moles of calcium gas = \(\frac{56 g}{40 g/mol}=1.4 moles\)

According to reaction, 1 mole of calcium react with 1 mole of chlorine gas.

Then 1.4 mol of calcium wiull react with :

\(\frac{1}{1}\times 1.4 = 1.4 mol\) chlorine gas

At standard temperature and pressure. 1 mol of gas occupies 22.4 L of volume.

Then 4.1 moles of chlorine gas will occupy :

\(22.4 L\tmes 4.1 =31.36 L\)

31.36 L of chlorine gas will react with 56 g of calcium.

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