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Abdul used a probability simulator to roll a 6-sided number cube and flip a coin 100 times. The results are shown in the tables below:



Using Abdul's simulation, what is the probability of rolling a '2' on the number cube and the coin landing on heads up?

A320/10000
B450/10000
C55/100
D65/100

Abdul used a probability simulator to roll a 6-sided number cube and flip a coin 100 times. The results are shown in the tables below: Using Abdul s simulation, class=

Verified Answer :

toporc

The simulation resulted in  the probability of rolling a 2 on the cube being 10/100 and the probability of heads being 45/100. The events 'rolling a 2' and 'tossing heads' are independent, therefore the probability of them occurring together is given by the product of the probabilities, as follows:
\(P(2\ and\ heads)=\frac{10}{100}\times\frac{45}{100}=\frac{450}{10000}\)
The correct choice is B.

Answer:

P( rolling 2 and head) =\(\frac{450}{10000}\) .

Step-by-step explanation:

Given : Abdul used a probability simulator to roll a 6-sided number cube and flip a coin 100 times. The results are shown in the tables below.

To find :  what is the probability of rolling a '2' on the number cube and the coin landing on heads up.

Solution : we have given :

Number 2 on cube rolled = 10 times

Total number of times it rolled = 100.

Probability  = \(\frac{Favorable\ outcome}{Total\ outcome}\).

Probability of 2 rolled on cube = \(\frac{10}{100}\).

coin landing on heads up = 45.

Total number of times coin flip = 100.

Probability of landing on heads up = \(\frac{45}{100}\).

Then, P( rolling 2 and head) = P( rolling 2) P( head).

Both are independent

P( rolling 2 and head) =\(\frac{10}{100}\)  \(\frac{45}{100}\).

P( rolling 2 and head) =\(\frac{450}{10000}\) .

Therefore, P( rolling 2 and head) =\(\frac{450}{10000}\) .

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