Solve and check....9^x = 3^x - 2
remember thatlogₐx=y means a^y=xalsoif a^n=a^m where a=a, then n=mtry to match basesremember that 9=3^29^x=3^(2x)3^(2x)=3^(x-2)2x=x-2minus x from both sidesx=-2x=-2to check9^-2=3^(-2-2)1/(9^2)=3^(-4)1/81=1/(3^4)1/81=1/81truex=-2
