we are given with the equation y = x^3 -9x^2 - 16x +1. It is said that when the slope is 5, there are two points tangent to the graph. the slope is equal to the y'.y' = 3x2 -18x -16 = 5 3x2 -18x - 21 = 0x1 = 7 and x2 = -1The two points are (7,-209) and (-1,7)
