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A block slides down a frictionless plane having an inclination of 15.0 degrees. The block starts from rest at the top, and the length of the incline is 2.00 m.

ADraw a free body diagram for the block.
BFind the acceleration of the block
CFind its speed when it reaches the bottom of the incline.

Verified Answer :

Formula for the questions b and c are the following: a = gsinΘ and V = √(2a*d)

The following are the answers to
the questions presented:

a. see attachment

b. 2.536 m/s^2 

c. 3.1852 m/s

I am hoping that these answers
have satisfied your queries and it will be able to help you in your endeavors, and
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View image Anonymous

Answer:

part b)

a = 2.54 m/s/s

part c)

v = 3.19 m/s

Explanation:

part b)

As we know that force due to gravity along the inclined plane is given as

\(F = mgsin\theta\)

acceleration of the object will be given as

\(a = \frac{F}{m}\)

\(a = gsin\theta\)

\(a = 9.8 sin15 = 2.54 m/s^2\)

part c)

As we know by kinematics

\(v_f^2 - v_i^2 = 2 a d\)

\(v_f^2 - 0 = 2(2.54)(2)\)

\(v_f^2 = 10.16\)

\(v_f = 3.19 m/s\)

View image aristocles

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