Answer : Frequency, \(u=\dfrac{1}{8}\ Hz\)
Explanation :
The equation of a particle executing SHM is given by :
\(y=A\ sin\omega t\).........(1)
Where,
y is the displacement
A is the amplitude of the wave
\(\omega\) is the angular frequency of the wave
t is the time
The given equation is :
\(y=5\ sin(\dfrac{\pi}{4})\ t\)............(2)
Comparing equation (1) and (2)
\(\because\ \omega=2\pi
u\)
So,
\(\dfrac{\pi}{4}=2\pi
u\)
\(u=\dfrac{1}{8}\ Hz\)
Hence, this is the required solution.
