Verified Answer :

False. You can pick any two numbers, but not the same number, to show its false. try it

Real number is the total of all numbers. The equation \(2a \cdot b = a^2 + b^2\) is false.

Given

\(2a \cdot b = a^2 + b^2\)

To prove or disprove the above equation, we simply assume values for a and b.

Assume that:

\(a=5\)

\(b = 6.7\)

The equation becomes:

\(2 \times 5 \times 6.7 = 5^2 + 6.7^2\)

\(67 = 25 + 44.89\)

\(67 = 68.89\)

The above equation is false

i.e. \(67 e 68.89\)

This means that: \(2a \cdot b = a^2 + b^2\) is false

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