Part 1:

Find the vertex, axis of symmetry, domain, and range of the graph of y = −2x^2 − 6x + 1.

Part 2:

Using complete sentences, explain how you can determine the axis of symmetry, the domain, and range without graphing y = −2x^2 − 6x + 1.

A quadratic equation is symmetrical around its vertex. The
equation for the axis of symmetry is x = -3/2 since the equation is in terms of
x. Since no value of x is undefined, then the domain of the equation is clearly
all real numbers. Since the value of “a” is negative, then that means the y
coordinate of the vertex is the maximum value so the range will never get above
11/2. I am hoping that these answers have satisfied your queries and it
will be able to help you in your endeavors, and if you would like, feel free to
ask another question.

Part 1:Find the vertex, axis of symmetry, domain, and range of the graph of y = −2x^2 − 6x + 1. Part 2:Using complete sentences, explain how you can determine the axis of symmetry, the domain, and range without graphing y = −2x^2 − 6x + 1.

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Related Questions

Part 1:

Find the vertex, axis of symmetry, domain, and range of the graph of y = −2x^2 − 6x + 1.

Part 2:

Using complete sentences, explain how you can determine the axis of symmetry, the domain, and range without graphing y = −2x^2 − 6x + 1.