which shows the correct substitution of the values a, b, and c from the equation 0 = 4x2 2x – 1 into the quadratic formula below? quadratic formula: x = -b±√b^2-4ac/2a
\(0 = 4x^2+2x- 1\)
Quadratic formula is
\(x = \frac{-b+-\sqrt{b^2-4ac}}{2a}\)
'a' is the coefficient of x^2 = 4
'b' is the coefficient of x = 2
'c' is the constant = -1
Now we plug in all the values in quadratic formula
\(x = \frac{-b+-\sqrt{b^2-4ac}}{2a}\)
\(x = \frac{-2+-\sqrt{2^2-4(4)(-1)}}{2(4)}\)
\(x = \frac{-2+-\sqrt{18}}{8}\)
The above one is the substitution of values of a,b,c in quadratic formula.
Answer:
Step-by-step explanation:
Its Option A for those who didn’t get the explanation.