Agneschellykes
Answered

the annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000. what is the z-score of a company employee who makes an annual salary of $54,000?

–5

–3

4

5

Verified Answer :

toporc

\(z=\frac{X-\mu}{\sigma}=\frac{54000-34000}{4000}=5\)

Answer:

z-score = 5

Step-by-step explanation:

the annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000.

To find z-score we use formula

z= \(\frac{x- mean}{standard \ deviation}\)

annual salary of $54,000, x is 54000

Plug in the values in the formula

z= \(\frac{x- mean}{standard \ deviation}\)

z= \(\frac{54000- 34000}{4000}=5\)

Related Questions