Answer:
\((5x^2+4y)(5x^2-4y)\)
Step-by-step explanation:
\(25x^4-16y^2\) has the form \(a^2-b^2\) known as a difference of squares. It factors into (a+b)(a-b). To find a and b you take the square root.
\(\sqrt{25x^4} =5x^2\)
\(\sqrt{16y^2} =4y\)
The factored for is (a+b)(a-b).
In this case, it is \((5x^2+4y)(5x^2-4y)\)
