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dgeorge231
dgeorge231 dgeorge231
  • 18-07-2016
  • Mathematics
Answered

What is the radius of a circle given by equation x^2 + y^2 - 2x + 8y - 47 = 0

Verified Answer :

padawan
padawan padawan
  • 23-07-2016

x^2 + y^2 - 2x + 8y - 47 = 0

x^2 + y^2 - 2x + 8y = 47

(x^2 - 2x) + (y^2 + 8y) = 47

(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47

(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2

(x - 1)^2 + (y + 4)^2 = 64 = 8^2

r=8

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plsmith2004
plsmith2004 plsmith2004
  • 30-04-2020

Answer:8

Step-by-step explanation:

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