Verified Answer :

caylus

Hello,

f(x,y)=e^y cos(x)-1-sin(xy)=0
@f/@x=-sin x e^y-ycos(xy)
@f/@y=cosx e^y-xsin(xy)

dy/dx=-(@f/@x)/(@f/@y)=(sin x e^y+ycos(xy))/(cos x e^y-xsin(xy)



meerkat18

Implicit expression refers to equation that are not strictly expressed in terms of y and x separately. In this case, the derivative of expression 
e^y cos(x) = 1 + sin(xy) is

-e^ y sin x dx + cos x e^y dy = cos (xy) (xdy + y dx)
dx (-e^ y sin x - y cosxy) = dy (x cos xy -cos x e^y)
dy/dx =  (-e^ y sin x - y cosxy) / (x cos xy -cos x e^y)

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