Verified Answer :

using the trigonometric equality:

sin(x+y)=sin(x)cos(y)+cos(x)sin(y)

then:

sin(90+θ)=sin(90)cos(θ)+cos(90)sin(θ)=cos(θ)

meerkat18

To prove this kind of equation you must use the Trigonometric Function of Equality. And came up with the formula of sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and then substitute the variables that is present if your function and came up with an answer of sin(90-theta)=sin(90)cos(theta)+cos(90)sin(theta)=cos(theta)
I hope i answered your question

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