Verified Answer :

meerkat18

We are given with the expression –5 + 2x² = –6x in which the standard form  is 2x² + 6x - 5 = 0 . There are two roots to be identified as expected. Through the quadratic equation, we can identify the a, b and c. Using the equation, the roots are 0.679 and -3.679. The expression is {0.679, -3.679}

calculista

Answer:

\(x=\frac{-3(+/-)\sqrt{19}} {2}\)

Step-by-step explanation:

we have

\(-5+2x^{2} =-6x\)

Rewrite

\(2x^{2}+6x-5=0\)

we know that

The formula to solve a quadratic equation of the form \(ax^{2} +bx+c=0\) is equal to

\(x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}\)

in this problem we have

\(2x^{2}+6x-5=0\)

so

\(a=2\\b=6\\c=-5\)

substitute

\(x=\frac{-6(+/-)\sqrt{6^{2}-4(2)(-5)}} {2(2)}\)

\(x=\frac{-6(+/-)\sqrt{76}} {4}\)

\(x=\frac{-6(+/-)2\sqrt{19}} {4}\)

simplify

\(x=\frac{-3(+/-)\sqrt{19}} {2}\)

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