sketch the graph: y = cot (pi/4 x). . well the period would be pi/b . - pi/ (pi/4 x). - I end up getting a period = 4. . HOW DO I FIND THE VERTICAL ASYMPTOTES?
The general form of the equation is acot (bx−c)+d to find the variables used to find the amplitude, period, phase shift, and vertical shift where a=1, b=π/4, c=0 and d=0
Period is pi/b or equal to 4.
The vertical asymptote is 4pi n where n is integer.
Attached is the sketch of the graph
Answer:
Refer the attached figure.
Vertical asymptote \(x=4+4n\)
Step-by-step explanation:
Given : Function \(y=\cot (\frac{\pi}{4}x)\)
To find : Sketch the given function and find the vertical asymptotes of the function ?
Solution :
Function \(y=\cot (\frac{\pi}{4}x)\)
Sketch the function on the graph.
Refer the attached figure.
Now, Vertical asymptote is defined as
On a graph, a line which is approached by a curve but never reached.
i.e. on different values of x y tends to infinity.
When we see the graph the vertical asymptote of the function is given by
\(x=4+4n\) for n=0,1,2,3...