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The correct answer among the choices presented above is option C. Barium hydroxide is the most basic solution. This can be proved by calculating the concentration of OH- ions in the solution. The one with the highest OH- concentration is the most basic solution.

NH3 is a weak base 
NH3 + H2O <=> NH4+ + OH- 
Kb = 1.8 x 10^-5 = x^2/0.6-x 
x = [OH-]= 0.0033 M 

KOH is a strong base so [OH-]= 0.150 M 

Ba(OH)2 = Ba2+ + 2 OH- 
[OH-]= 2 x 0.100 = 0.200 M

The solution which is most basic is c) 0.100 M Ba(OH)₂ , this can be calculated by the concentration of OH- ions.

Calculation for concentartion of OH-:

This can be proved by calculating the concentration of OH- ions in the solution. The one with the highest OH- concentration is the most basic solution.

NH₃ is a weak base

\(NH_3 + H_2O < = > NH_4^+ + OH^-\)

\(K_b = 1.8 x 10^{-5}\\\\K_b= x^2/0.6-x \\\\x = [OH^-]= 0.0033 M\)

KOH is a strong base.

So, \([OH^-]= 0.150 M\)

\(Ba(OH)_2 < = > Ba^{2+} + 2 OH^-\)

\([OH^-]= 2 * 0.100 = 0.200 M\)

Thus, the solution which is most basic is c) 0.100 M Ba(OH)₂.

Find more information about Concentration of OH- here:

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