Use the conversion factor 1amu=6.66054 x 10^-24 to answer the following questions.. . a) 1.674 x 10^-24 g of neutrons is how many amu?. . b)what is the mass in grams of one lithium atom(lithium has an atomic weight of 6.94 amu). . c)6.492 x 10^-23 g of potassium is how many amu?

Verified Answer :

a.) The conversion factor is 1 amu = \(1.66054 ^{-24}g\)

To know how many amu in \(1.674x10^{-24}g\) grams of neutrons:
\(1.674x10^{-24}g ( \frac{x (amu) }{ 1.66054x10^{-24} g)}\)

=1.00811 amu

b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.

\(6.94 amu (\frac{6.66054 ^{-24} g}{1 amu})\) = \(4.62241x10 ^{23} g\)

c.) How many amu in 6.492x10^-23g potassium?

\(6.492x10^{-23}g ( \frac{x (amu) }{ 1.66054x10^{-24}g })\) = 39.0957 amu


Answer :

(a) The number of amu is 1.008 amu.

(b) The mass of one lithium atom is \(11.5\times 10^{-24}g\)

(c) The number of amu is 39.09 amu.

Explanation :

As we are given that conversion factor:

\(1amu=1.66054\times 10^{-24}g\)

(a) To calculate the number of amu.

As, \(1.66054\times 10^{-24}g\) of neutrons = 1 amu

So, \(1.674\times 10^{-24}g\) of neutrons = \(\frac{1.674\times 10^{-24}g}{1.66054\times 10^{-24}g}\times 1amu=1.008amu\)

Thus, the number of amu is 1.008 amu.

(b) To calculate the mass of one lithium atom.

As, 1 amu of lithium atom = \(1.66054\times 10^{-24}g\)

So, 6.94 amu of lithium atom = \(6.94\times 1.66054\times 10^{-24}g=11.5\times 10^{-24}g\)

Thus, the mass of one lithium atom is \(11.5\times 10^{-24}g\)

(c) To calculate the number of amu.

As, \(1.66054\times 10^{-24}g\) of neutrons = 1 amu

So, \(6.492\times 10^{-23}g\) of neutrons = \(\frac{6.492\times 10^{-23}g}{1.66054\times 10^{-24}g}\times 1amu=39.09amu\)

Thus, the number of amu is 39.09 amu.