Verified Answer :
a.) The conversion factor is 1 amu = \(1.66054 ^{-24}g\)
To know how many amu in \(1.674x10^{-24}g\) grams of neutrons:
\(1.674x10^{-24}g ( \frac{x (amu) }{ 1.66054x10^{-24} g)}\)
=1.00811 amu
b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.
\(6.94 amu (\frac{6.66054 ^{-24} g}{1 amu})\) = \(4.62241x10 ^{23} g\)
c.) How many amu in 6.492x10^-23g potassium?
\(6.492x10^{-23}g ( \frac{x (amu) }{ 1.66054x10^{-24}g })\) = 39.0957 amu
Answer :
(a) The number of amu is 1.008 amu.
(b) The mass of one lithium atom is \(11.5\times 10^{-24}g\)
(c) The number of amu is 39.09 amu.
Explanation :
As we are given that conversion factor:
\(1amu=1.66054\times 10^{-24}g\)
(a) To calculate the number of amu.
As, \(1.66054\times 10^{-24}g\) of neutrons = 1 amu
So, \(1.674\times 10^{-24}g\) of neutrons = \(\frac{1.674\times 10^{-24}g}{1.66054\times 10^{-24}g}\times 1amu=1.008amu\)
Thus, the number of amu is 1.008 amu.
(b) To calculate the mass of one lithium atom.
As, 1 amu of lithium atom = \(1.66054\times 10^{-24}g\)
So, 6.94 amu of lithium atom = \(6.94\times 1.66054\times 10^{-24}g=11.5\times 10^{-24}g\)
Thus, the mass of one lithium atom is \(11.5\times 10^{-24}g\)
(c) To calculate the number of amu.
As, \(1.66054\times 10^{-24}g\) of neutrons = 1 amu
So, \(6.492\times 10^{-23}g\) of neutrons = \(\frac{6.492\times 10^{-23}g}{1.66054\times 10^{-24}g}\times 1amu=39.09amu\)
Thus, the number of amu is 39.09 amu.