\(The\ slope-point\ form:y-y_1=m(x-x_1)\\m=\dfrac{y_2-y_1}{x_2-x_1}\\---------------------\\(-3;\ 2)\to x_1=-3\ and\ y_1=2\\(2;\ 1)\to x_2=2\ and\ y_2=1\\\\m=\dfrac{1-2}{2-(-3)}=\dfrac{-1}{5}=-\dfrac{1}{5}\\\\for\ (-3;\ 2)\\y-2=-\dfrac{1}{5}(x-(-3))\to y-2=-\dfrac{1}{5}(x+3)\\\\for\ (2;\ 1)\\y-1=-\dfrac{1}{5}(x+2)\)