Answer:
The quadratic equations are \(7x^2 + 14x = 0\), \(x^2 + 3x -5 = 0\) and \(x^2 - x = 3x + 7\).
Step-by-step explanation:
Consider the provided information.
We need to find all the quadratic equations.
The given equations are:
\(7x^2 + 14x = 0\)
\(x^3 - 3x^2 + 1 = 0\)
\(5x - 7 = 0\)
\(x^2 + 3x -5 = 0\)
\(x - 5 = 9x + 7\)
\(x^2 - x = 3x + 7\)
Quadratic equations is an equation of the second degree (degree is the highest power of x).
Now consider the provided options:
The equations having second degree are:
\(7x^2 + 14x = 0\) The highest power of x is 2.
\(x^2 + 3x -5 = 0\) The highest power of x is 2.
\(x^2 - x = 3x + 7\) The highest power of x is 2.
Hence, the quadratic equations are \(7x^2 + 14x = 0\), \(x^2 + 3x -5 = 0\) and \(x^2 - x = 3x + 7\).
