Verified Answer :

dalendrk

\(\dfrac{95^o}{360^o}=\dfrac{19}{72}\\\\Perimeter\ of\ the\ circle:L=2\pi\cdot6=12\pi\approx12\cdot3.14=37.68\\\\\widehat{DG}=\dfrac{19}{72}\cdot37.68\approx9.95\\\\Answer:\boxed{9.95}\)

Panoyin

Degrees: \(s = \frac{\pi}{180}\theta r\)
                \(s = \frac{\pi}{180}(\frac{s}{r})(r)\)
                \(s = \frac{\pi}{180}(\frac{95}{6})(6)\)
                \(s = \frac{\pi}{180}(15.8\bar{3})(6)\)
                \(s = \frac{\pi}{180}(95)\)
                \(s = \frac{95\pi}{180}\)
                \(s = \frac{19\pi}{36}\)
                \(s = 95\°\)

Radians: \(s = \theta r\)
               \(s = \frac{95}{6}(6)\)
               \(s = 95\)
               \(s = \frac{19\pi}{36}\)

Arc Length = \(\frac{\theta}{360} * C\)
Arc Length = \(\frac{95}{360} * 2(3.14)(6)\)
Arc Length = \(\frac{19}{72} * 2(18.84)\)
Arc Length = \(\frac{19}{72} * 37.68\)
Arc Length = \(\frac{715.92}{72}\)
Arc Length = \(9.94\bar{3}\)

The answer is A.

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