how do u do this whole qn?
(i)\(P(zero\ bombs)=\frac{20C0\times 380C10}{400C10}=0.595\)(ii)\(P(zero\ bombs)=\frac{40C0\times 360C10}{400C10}=0.344\) P(one or more bombs) = 1.000 - 0.344 = 0.656