Braniac
Answered

Change the equation to show what it would look like if you were getting the value of (b):
Show steps please.

\(A= \frac{1}{2}h(b+c)\)

Verified Answer :

luana

\(A=\frac{1}{2}h(b+c)\ \ \ \ \ |multiply\ by\ 2\\\\ 2a=h(b+c)\ \ \ \ |divide\ by\ h\\\\ \frac{2a}{h}=b+c\ \ \ \ \ |subtract\ c\\\\ \frac{2a}{h}-c=b\\\\Solution\ is\ b=\frac{2a}{h}-c\)

konrad509

\(A= \frac{1}{2}h(b+c) \\ 2A=h(b+c)\\ 2A=hb+hc\\ hb=2A-hc\\ b=\frac{2A-hc}{h}\)

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