Answer: \(3.75\times10^{-3}\) seconds
Step-by-step explanation:
Given: Time taken by computer program in Shannon's computer carries a single mathematical operation=\(1.5\times10^{-6}\) seconds
Time taken by computer program to carry a \(2.5\times10^3\) mathematical operation is given by :-
\(2.5\times10^3\times1.5\times10^{-6}\\\\=(2.5\times1.5)\times(10^3\times10^{-6})\\\\=3.75\times10^{3+(-6)}=3.75\times10^{3-6}\\\\=3.75\times10^{-3}\)
Hence, Time taken by computer program to carry a \(2.5\times10^3\) mathematical operation is \(3.75\times10^{-3}\) seconds
