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John is playing a game of darts. The probability that he throws a dart into the center of the dart board (the Bull’s eye) is . The probability that he throws the dart into the 10-point ring is .. . What is the probability that he either hits a Bull’s eye or scores 10 points?. . A-1/3. B-2/3. C-3/5. D-2/5. E-1/4

Verified Answer :

The probability that he either hits a Bull’s eye
or scores 10 points is 2/5.

 

The correct answer between all
the choices given is the fourth choice or letter D. I am hoping that this
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MrRoyal

The probability that he either hits a Bull’s eye or score 10 points is 2/5

How to determine the probability?

The given parameters are:

  • P(Hit bullseye) = 1/10
  • P(Score 10) = 3/10

The probability that he either hits a Bull’s eye or score 10 points is then calculated using:

P = P(Hit bullseye) + P(Score 10)

So, we have:

P = 1/10 + 3/10

Evaluate the sum

P = 4/10

Simplify the fraction

P = 2/5

Hence, the probability that he either hits a Bull’s eye or score 10 points is 2/5

Read more about probability at:

https://brainly.com/question/1270307

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