A boy stands 1 meter away from a lamppost. He is 1.8 meters tall and casts a shadow 2 meters long in the light from the lamp
The diagram is attached below using the given information
We have two similar triangle
Triangle ACD is similar to triangle ABE. So the sides are in proportional
\(\frac{DC}{EB} =\frac{AC}{AB}\)
AC = AB + BC = 3m
\(\frac{x}{1.8}=\frac{3}{2}\)
2x = 1.8 * 3 (cross multiply)
2x = 5.4
Divide by 2 on both sides
x = 2.7
Height of Lamppost is 2.7 meter
