The work done on the box by the weight of the box is 1.8 Joule
The work done on the box by the normal force is 0 Joule
The work done on the box by the force of kinetic friction is -0.918 Joule
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Further explanation
Let's recall Kinetic Energy Formula as follows:
\(Ek = \frac{1}{2}mv^2\)
Ek = Kinetic Energy ( Joule )
m = mass of the object ( kg )
v = speed of the object ( m/s )
Let us now tackle the problem !
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Given:
weight of the box = w = 2.0 N
angle of inclined plane = θ = 30°
normal force = N = 1.7 N
coefficient of kinetic friction = μ = 0.30
displacement of the box = d = 1.8 m
Asked:
work done by weight = W_w = ?
work done by normal force = W_n = ?
work done by the force of kinetic friction = W_f = ?
Solution:
We could calculate work done by weight as follows:
\(W_w = w \times h\)
\(W_w = w \times d \times \sin \theta\)
\(W_w = 2.0 \times 1.8 \times \sin 30^o\)
\(W_w = 2.0 \times 1.8 \times \frac{1}{2}\)
\(W_w = 1.8 \texttt{ Joule}\)
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Because the direction of displacement is perpendicular to the direction of normal force , then:
\(W_n = N \times d \times \cos \theta\)
\(W_n = 1.7 \times 1.8 \times \cos 90^o\)
\(W_n = 0 \texttt{ Joule}\)
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Finally, we could calculate the work done by friction as follows:
\(W_f = -f \times d\)
\(W_f = -\mu_k \times N \times d\)
\(W_f = -0.30 \times 1.7 \times 1.8\)
\(W_f = -0.918 \texttt{ Joule}\)
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Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
- The Acceleration Due To Gravity : https://brainly.com/question/4189441
- Newton's Law of Motion: https://brainly.com/question/10431582
- Example of Newton's Law: https://brainly.com/question/498822
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Answer details
Grade: High School
Subject: Physics
Chapter: Dynamics
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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
