Verified Answer :

H₂CO₃ = 2 1 + 12 + 316 = 62 g / mol

0.8 mole of it.

Mass = 0.8 * 62 = 49.6 g 

Answer : The mass of \(H_2CO_3\) is, 49.6 grams

Solution : Given,

Moles of \(H_2CO_3\) = 0.800 mole

Molar mass of \(H_2CO_3\) = 62 g/mole

Formula used :

\(\text{Moles of }H_2CO_3=\frac{\text{Mass of }H_2CO_3}{\text{Molar mass of }H_2CO_3}\)

Now put all the given values in this formula, we get the mass of \(H_2CO_3\)

\(0.800mole=\frac{\text{Mass of }H_2CO_3}{62g/mole}\)

\(\text{Mass of }H_2CO_3=49.6g\)

Therefore, the mass of \(H_2CO_3\) is, 49.6 grams