Calculate the mass in grams of 0.800 mole of H2CO3.. . 1)49.6. 2)23. 3)78
H₂CO₃ = 2 1 + 12 + 316 = 62 g / mol
0.8 mole of it.
Mass = 0.8 * 62 = 49.6 g
Answer : The mass of \(H_2CO_3\) is, 49.6 grams
Solution : Given,
Moles of \(H_2CO_3\) = 0.800 mole
Molar mass of \(H_2CO_3\) = 62 g/mole
Formula used :
\(\text{Moles of }H_2CO_3=\frac{\text{Mass of }H_2CO_3}{\text{Molar mass of }H_2CO_3}\)
Now put all the given values in this formula, we get the mass of \(H_2CO_3\)
\(0.800mole=\frac{\text{Mass of }H_2CO_3}{62g/mole}\)
\(\text{Mass of }H_2CO_3=49.6g\)
Therefore, the mass of \(H_2CO_3\) is, 49.6 grams