move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula
for an equation in the form
ax^2+bx+c=0
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)
a=3
b=4
c=5
x=\(\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}\)
x=\(\frac{-4+/- \sqrt{16-60} }{6}\)
x=\(\frac{-4+/- \sqrt{-44} }{6}\)
x=\(\frac{-4+/- 2\sqrt{-11} }{6}\)
remember that√-1=i
x=\(\frac{-4+/- 2i\sqrt{-11} }{6}\)
x=\(\frac{-2+/- i\sqrt{-11} }{3}\)
x=\(\frac{-2+ i\sqrt{-11} }{3}\) or x=\(\frac{-2- i\sqrt{-11} }{3}\)
