For this case we have the following polynomial:
\(2x^2 - 5x + 1 = 3
\)
Rewriting the polynomial we have:
\(2x^2 - 5x + 1 - 3 = 0
2x^2 - 5x - 2 = 0
\)
Using the quadratic formula to find the solutions we have:
\(x = \frac{-b+/-\sqrt{b^2 - 4ac}}{2a}\)
Substituting values:
\(x = \frac{-(-5)+/-\sqrt{(-5)^2 - 4(2)(-2)}}{2(2)}\)
Rewriting:
\(x = \frac{5+/-\sqrt{25+16}}{4}\)
\(x = \frac{5+/-\sqrt{41}}{4}\)
Solution 1:
\(x = \frac{5+\sqrt{41}}{4}\)
Solution 2:
\(x = \frac{5-\sqrt{41}}{4}\)
