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tianamfarmer
tianamfarmer tianamfarmer
  • 14-07-2016
  • Mathematics
Answered

evaluate

9C5

and

11P4

.

Verified Answer :

konrad509
konrad509 konrad509
  • 14-07-2016

\(9C5=\dfrac{9!}{5!4!}=\dfrac{6\cdot7\cdot8\cdot9}{2\cdot3\cdot4}=6\cdot7\cdot3=126\\\\ 11P4=\dfrac{11!}{7!}=8\cdot9\cdot10\cdot11=7920\)

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