Verified Answer :

susie098

P(2 aces) = (1/13)^2 
P(2 kings) = (1/13)^2 

P(king and ace) = 8C2/52C2 - 2(1/13)^2 = 0.0152

Answer:

\(\frac{1}{169}\)

Step-by-step explanation:

Total cards = 52

Total ace = 4

So probability of getting ace on first draw = \(\frac{4}{52}\)

Now the card is replaced .

So, Total cards = 52

Total kings = 4

So probability of getting kings on second draw = \(\frac{4}{52}\)

So,  the probability of choosing a king and an ace:

=  \(\frac{4}{52} \times \frac{4}{52}\)

=  \(\frac{1}{169}\)

Hence the probability of choosing a king and an ace is  \(\frac{1}{169}\)

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