what are the solutions to m2 – 9 = 0
(m-3)(m+3) = 0m = 3 , - 3
Answer:
The solutions are \(m=3, m=-3\)
Step-by-step explanation:
we have
\(m^{2}-9=0\)
Solve for m
Adds \(9\) both sides
\(m^{2}-9+9=0+9\)
\(m^{2}=9\)
Take the root square both sides
\(m=(+/-)\sqrt{9}\)
\(m=(+/-)3\)
therefore
\(m=3, m=-3\)
