Answer:
The value of \(g(f(-1))=\frac{1}{2}\)
Step-by-step explanation:
Given : \(f(x)=x^2\) and \(g(x)=\frac{1}{2}x^3\)
To find : The value of \(g(f(-1))\)?
Solution :
First we find the function g(f(x)),
Which means substitute the value of f(x) in g(x)
\(g(f(x))=\frac{1}{2}(x^2)^3\)
\(g(f(x))=\frac{1}{2}(x^6)\)
Now, we put the value of x=-1
\(g(f(-1))=\frac{1}{2}(-1^6)\)
\(g(f(-1))=\frac{1}{2}(1)\)
\(g(f(-1))=\frac{1}{2}\)
Therefore, The value of \(g(f(-1))=\frac{1}{2}\)
