The answer is 6.7 miles further.
It is given:
\(d= \sqrt{ \frac{3h}{2}}\)
Wyatt’s eye-level height - h₁ = 120ft
Shawn’s eye-level height - h₂ = 270ft
The distance that Wyatt can see:
\(d_1= \sqrt{ \frac{3h_1}{2}} = \sqrt{ \frac{3*120}{2 }}= \sqrt{180} =13.42miles\)
The distance that Shawn can see:
\(d_2= \sqrt{ \frac{3h_2}{2}}= \sqrt{ \frac{3*270}{2} }= \sqrt{405}=20.12 miles\)
The question is how much farther can Shawn see to the horizon, so we need to subtract the results:
20.12 - 13.42 = 6.7 miles
