This is a geometric progression
The size of the population afeter t hours will be=a₁r^n
a₁= the first term =200
r=common ratio=4
150 minutes=150 minutes (1 hour /60 minutes)=2.5 hours.
In this case:
the size of the populatation after t hours=2004^t/2.5=2004^0.4t
To check
t=0⇒ the size will be=2004⁰=2001=200
t=2.5 hours=150 minutes; the size will be =2004¹=800
t=5 hours; the size will be=2004²=20016=3200
Answer: the size will be= 2004^(0.4t)
