Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula? Quadratic formula:

Verified Answer :

\(1=-2x+3x^2+1\\\\3x^2-2x+1-1=0\\\\3x^2-2x=0\\\\\boxed{a=3;\ b=-2;\ c=0}\)

Answer:

\(a=3\),  \(b=-2\) and  \(c=0\).

Step-by-step explanation:

We have been given an equation \(1=-2x+3x^2+1\).

We know that a quadratic equation is in form \(ax^2+bx+c\).

First of all, we need to convert our given equation in standard quadratic equation as shown:

\(1-1=-2x+3x^2+1-1\)

\(0=-2x+3x^2\)

\(-2x+3x^2=0\)

\(3x^2-2x=0\)

Upon comparing our equation with standard quadratic equation we can see that \(a=3\),  \(b=-2\) and  \(c=0\).