Verified Answer :

nobillionaireNobley

Angle θ between two vectors is given by, \(\theta =cos^{-1}( \frac{u \cdot v}{|u||v|} )\); where \(u \cdot v=8(9)+(7)(7)=72+49=121\); \(|u|= \sqrt{ 8^{2} + 7^{2} } = \sqrt{64+49} = \sqrt{113}\) and \(|v|=\sqrt{ 9^{2} + 7^{2} } = \sqrt{81+49} = \sqrt{130}\).
Therefore, \(\theta =cos^{-1}( \frac{121}{ \sqrt{113} \times \sqrt{130} } )=cos^{-1}0.9983=3.3^o\)

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