it is in form
0=ax^2+bx+c
0=-3x^2-2x+6
a=-3
b=-2
c=6
so
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)
x=\(\frac{-(-2)+/- \sqrt{(-2)^2-4(-3)(6)} }{2(-3)}\)
x=\(\frac{2+/- \sqrt{4+72} }{-6}\)
x=\(\frac{2+/- \sqrt{76} }{-6}\)
x=\(\frac{2+/- 2\sqrt{19} }{-6}\)
x=\(\frac{1+/- \sqrt{19} }{-3}\)
x=\(\frac{1+ \sqrt{19} }{-3}\) or \(\frac{1- \sqrt{19} }{-3}\)
