Answer:
x=6, y=8
Step-by-step explanation:
First, we can put the sytem of equations in standard form, it holds that
\(y-\dfrac{1}{3}x=-10\\\\\\y+2x=4\)
then, we can substract the second equation from the first equation to get that
\((\dfrac{-1}{3}-2)x=-10-4\quad\Rightarrow\quad \dfrac{-7}{3}x=-14\\\\\quad\Rightarrow\quad x=6\)
Finally, we use this result in the first equation to get that
\(y-\dfrac{1}{3}\cdot 6=-10\quad\Rightarrow\quad y-2=-10\quad\Rightarrow y=8\)
