Verified Answer :

\(\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]\)

Isolate x for \(ax+by=r\)

\(x= \frac{r-by}{a} ; a eq 0\)

Subsititute \(x= \frac{r-by}{a}\)

\(-b \frac{r-by}{a} +cy=s\)

Isolate r for : \(-b \frac{r-by}{a}+cy=s\)

\(r=- \frac{as-acy-b^2y}{b} ; a eq 0;b eq 0\)

For x : \(\frac{r-by}{a}\)

Subsititute r = \(- \frac{as-acy-b^2y}{b}\)

\(x= -\frac{as-acy-b^2y}{b}/a\)

\(x = \frac{cy-s}{b}\)

The solutions to the system of equations are:

\(r= -\frac{as-acy-b^2y}{b}\) and  \(x = \frac{cy-s}{b}\)

hope this helps!