By how much does a3 - 2a exceed a2 + a - 6?
\(a^3-2a-(a^2+a-6)=a^3-2a-a^2-a+6=a^3-a^2-3a+6\)
Hello,Let's d the exceed number.d=a^3-2a-(a²+a-6)=a^3-2a-a²-a+6=a^3-a²-3a+6